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awk to print a pattern

原文 2017-03-06 11:47:49 3 1 linux/ unix/ awk

I have a huge text file where I want to print the column contains the word ````

LastRechargeDate= xxxx

where:

xxxx is deferent dates

this word/pattern is mostly can be found in column 13. so, I used the following awk command

nawk -F "," | print '{print $1, $13}'

my issue here is that, the word i want to print in some lines is located in column 23, some lines in column 19

1 answers

assuming date is not a regex complication ...

awk -F ',' -v Pat="LastRechargeDate= xxxx" ' '$0 ~ Pat { for (i=2;i<NF;i++) if ( $i ~ Pat ) print $1 "," $i }' YourFile

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