Passing two parameters into shell script

Question

Im very new shell script. Im ran the below sqoop command in shell script and got the result.

sqoop command in shell script

#!/bin/bash
while read table; do
sqoop eval --connect jdbc:mysql://127.0.0.1/mydb --username root --password cloudera --query "describe $table"
done<tables.txt

Input file: tables.txt has just one word: MYTAB And Im gettting result for that.

But how can I write a script to take two parameters from the file when data in tables.txt looks like this: MYDB:MYTAB and I want to pass dbname and table name to my sqoop command in the script which looks like below.

#!/bin/bash
while read table; do
sqoop eval --connect jdbc:mysql://127.0.0.1/$dbname --username root --password cloudera --query "describe $table"
done<tables.txt

Can anyone tell me how to extract the values from the file and put them in the file ?

Answer 1

在将适当的字段分隔符IFS设置为之后，更改您的read语句:

while IFS=":" read -r dbname table; do