def main():
option=displaymenu()
print(option)
while option1 != 4:
if option1 ==1:
print("1234")
elif option1==2:
print("1")
elif option1==3:
print("joe")
else:
print("end")
def displaymenu():
print("choose one of the following options")
print("1.Calculate x to the power of N") << this is supposed to be
print("2.Calculate factorial of N")
print("3.Calculate EXP")
print("4.Exit")
option1=input("Please enter your choice here:")<<< i want these print statements to act as a menu? how do I make it so when I input a number 1-4 It does this operation I input ?
I want this to be a input statement that when I input 1 it will do print 1234 as I coded in my main program... help ? why when I enter a 1 or 2 or 3 it does nothing but print "end" ..? help. main()
Your line option=displaymenu()
will set option
to None
as you don't have a return statement at the end of your function. Add the following line to your function and it should work:
return int(option1)
You are not returning back option1 from displaymeny. Instead you are trying to access it in the main function:
while option1 != 4:
This also means that option in the main function does not have any vaule.
Change your program to this:
def main():
option = -1 # Value to get the while loop started
while option != 4:
option=displaymenu()
if option ==1:
print("1234")
elif option==2:
print("1")
elif option==3:
print("joe")
else:
print("end")
def displaymenu():
print("choose one of the following options")
print("1.Calculate x to the power of N") << this is supposed to be
print("2.Calculate factorial of N")
print("3.Calculate EXP")
print("4.Exit")
return input("Please enter your choice here:")<<< i want these print statements to act as a menu? how do I make it so when I input a number 1-4 It does this operation I input ?
Also note that I moved the call to displaymeny inside the while loop. If you have it outside you will only get the menu once.
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