I'm trying to remove sublists from a nested list containing all the possible permutation of [1, 1, 1, 0, 0, 0, 0]
[[0, 1, 0, 1, 0, 0, 1], [0, 1, 0, 0, 1, 1, 0], [0, 0, 1, 1, 0, 0, 1], [0, 0, 1, 1, 1, 0, 0], [0, 1, 1, 0, 0, 1, 0], [1, 0, 0, 0, 1, 1, 0], [0, 0, 1, 0, 0, 1, 1], [0, 0, 1, 0, 1, 1, 0], [0, 0, 1, 0, 1, 0, 1], [0, 1, 0, 0, 0, 1, 1], [0, 1, 1, 1, 0, 0, 0], [1, 1, 0, 0, 1, 0, 0], [0, 1, 0, 0, 1, 0, 1], [1, 1, 0, 1, 0, 0, 0], [0, 1, 0, 1, 1, 0, 0], [1, 0, 1, 1, 0, 0, 0], [0, 1, 1, 0, 1, 0, 0], [0, 1, 0, 1, 0, 1, 0], [1, 0, 0, 1, 1, 0, 0], [0, 0, 0, 1, 0, 1, 1], [1, 0, 1, 0, 1, 0, 0], [1, 1, 0, 0, 0, 1, 0], [1, 0, 0, 0, 0, 1, 1], [1, 0, 1, 0, 0, 1, 0], [0, 0, 0, 0, 1, 1, 1], [0, 0, 0, 1, 1, 0, 1], [0, 0, 0, 1, 1, 1, 0], [1, 0, 0, 0, 1, 0, 1], [1, 1, 1, 0, 0, 0, 0], [0, 1, 1, 0, 0, 0, 1], [1, 0, 0, 1, 0, 1, 0], [1, 0, 0, 1, 0, 0, 1], [1, 1, 0, 0, 0, 0, 1], [1, 0, 1, 0, 0, 0, 1], [0, 0, 1, 1, 0, 1, 0]]
I want to remove all the sublists in which there are 3 consecutive 0 or two couples of consecutive 0 (eg. i want to remove [1, 0, 1, 0, 0, 0, 1]
or [0, 0, 1, 1, 0, 0, 1]
).
Can someone give me an advice on how to proceed? Thanks in advance!
You could define such a methode to find out if a given permutation p
has those triple zeros or two double zeros :
def has_triple_zeros(p):
for i, e in enumerate(p[:-2]): # e are elements (0s and 1s) of the perm
if e == 0: # we encounter a 0
if p[i+1] == 0 and p[i+2] == 0: # the two following are also 0s
return True
return False # we made it to the end, no triple 0s
def has_two_double_zeros(p):
nb_doubles = 0
i = 0 # init loop
while i < len(p[:-1]):
if p[i] == 0: # we encounter a first 0
if p[i+1] == 0: # there is one next to it
nb_doubles += 1
i += 1 # skip the next element (already treated, cannot start new double)
i += 1 # increment the loop
return nb_doubles == 2
for p in lst: # here, lst is your list of permutations
print(p, has_two_double_zeros(p), has_triple_zeros(p))
Then just read your list of permutations and delete if it matches one of your criteria. This is an idea:
res = list() # result
for p in lst:
if not (has_two_double_zeros(p) or has_triple_zeros(p)):
res.append(p)
print(res)
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