how to get value from a string using regular expression in php

Question

this is my string

$string = "<table><tr><td><a href="https://rads.stackoverflow.com/amzn/click/com/B01IG6C0D4" rel="nofollow noreferrer" target="_blank"><img src="https://images-na.ssl-images-amazon.com/images/I/41ltpJWi8jL._SL160_.jpg" alt="Product Image" style='border:0'/></a></td><td><tr><td>List Price <strike>$17.99</strike></td></tr><tr><td><b>Deal Price: $11.04</b></td></tr><tr><td>You Save: $6.95 (39%)</td></tr><tr><td>Save on the AmazonBasics Foldable Laundry Hamper</td></tr><tr><td>Expires Apr 28, 2017</td></tr></td></tr>";

please help me to extract the 39% (it ca be changed) from this string using regular expression in PHP. I am weak in the regular expression.

Thanks in advance

Answer 1

Using the following regex (one or more digits followed by a % sign) I am able to get the match:

(\d+)\%

Example - https://regex101.com/r/a36Zdl/1

Answer 2

Use the preg_match() function to match the pattern \\d{1,}\\s*% means one or more digits (0-9) followed by space or not and finally followed by % signal.

preg_match() return if the pattern was matched or not, in case of positive the string (captured) will be store in the third argument ( $m ).

$string = '<table><tr><td><a href="http://rads.stackoverflow.com/amzn/click/B01IG6C0D4" target="_blank"><img src="https://images-na.ssl-images-amazon.com/images/I/41ltpJWi8jL._SL160_.jpg" alt="Product Image" style=border:0/></a></td><td><tr><td>List Price <strike>$17.99</strike></td></tr><tr><td><b>Deal Price: $11.04</b></td></tr><tr><td>You Save: $6.95 (**39%**)</td></tr><tr><td>Save on the AmazonBasics Foldable Laundry Hamper</td></tr><tr><td>Expires Apr 28, 2017</td></tr></td></tr>';
preg_match('/\d{1,}\s*%/', $string, $m);

To capture a number with a fraction this regex (\\d{1,}|\\d{1,}\\.\\d{1,})\\s*% sounds better

$string = 'asdasd 36.45%';
echo preg_match('/(\d{1,}|\d{1,}\.\d{1,})\s*%/', $string, $m);