I've faced some really strange behavior trying to calculate md5 hash of string. Returned hash is always wrong (and different) if I pass string that was result of concatenation. Only way to get real hash I've found is to pass string that wasn't modified in any way after creation.
Python 2.7.13 (v2.7.13:a06454b1afa1, Dec 17 2016, 20:42:59) [MSC v.1500 32 bit (Intel)] on win32
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>>> import hashlib
>>> m = hashlib.md5()
>>> a1 = "stack"
>>> a2 = "overflow"
>>> a3 = a1 + a2
>>> a4 = str(a1 + a2)
>>> m.update("stackoverflow")
>>> m.hexdigest()
'73868cb1848a216984dca1b6b0ee37bc' //actuall hash
>>> m.update(a1 + a2)
>>> m.hexdigest()
'458b7358b9e0c3f561957b96e543c5a8'
>>> m.update(a3)
>>> m.hexdigest()
'65b0e62d4ff2d91e111ecc8f27f0e8f5'
>>> m.update(a4)
>>> m.hexdigest()
'60c3ae3dd9a2095340b2e024194bad3c'
>>> m.update(a1 + a2)
>>> m.hexdigest()
'acd4e14145d34dcb10af785badf8e73e'
>>> m.update(a1 + a2)
>>> m.hexdigest()
'03c06ca09faa26166f1096db02272b11'
>>> a1 + a2 == a1 + a2
True
>>> a1 + a2 == a3
True
>>> a3 == a4
True
Am I missing something?
What you are missing is that hash.update()
doesn't replace the hashed data . You are continually updating the hash object, so you are getting the hash of the concatenated strings . From the hashlib.hash.update()
documentation :
Update the hash object with the string arg . Repeated calls are equivalent to a single call with the concatenation of all the arguments:
m.update(a)
;m.update(b)
is equivalent tom.update(a+b)
.
Bold emphasis mine.
So you are not getting the hash of a single 'stackoverflow'
string, you are getting the hash first of 'stackoverflow'
, then of 'stackoverflowstackoverflow'
, then 'stackoverflowstackoverflowstackoverflow'
etc., each time appending another 'stackoverflow'
creating a longer and longer string. None of those longer strings are equal to the original short string so their hashes are not likely to be equal either.
Create a new object for new strings, instead:
>>> import hashlib
>>> m = hashlib.md5()
>>> m.update('stack' + 'overflow')
>>> m.hexdigest()
'73868cb1848a216984dca1b6b0ee37bc'
>>> m = hashlib.md5() # **new** hash object
>>> m.update('stackoverflow')
>>> m.hexdigest()
'73868cb1848a216984dca1b6b0ee37bc'
>>> m = hashlib.md5() # new object again
>>> m.update('stack') # add the string in pieces, part 1
>>> m.update('overflow') # and part 2
>>> m.hexdigest()
'73868cb1848a216984dca1b6b0ee37bc'
You can readily produce your 'wrong' hashes by sending in concatenated data:
>>> m = hashlib.md5()
>>> m.update('stackoverflowstackoverflow')
>>> m.hexdigest()
'458b7358b9e0c3f561957b96e543c5a8'
>>> m = hashlib.md5()
>>> m.update('stackoverflowstackoverflowstackoverflow')
>>> m.hexdigest()
'65b0e62d4ff2d91e111ecc8f27f0e8f5'
>>> m = hashlib.md5()
>>> m.update('stackoverflow' * 4)
>>> m.hexdigest()
'60c3ae3dd9a2095340b2e024194bad3c'
Note that you can also pass in the first string into the md5()
function:
>>> hashlib.md5('stackoverflow').hexdigest()
'73868cb1848a216984dca1b6b0ee37bc'
You normally use the hash.update()
method only if you are processing data in chunks (like reading a file line by line or reading blocks of data from a socket), and don't want to have to hold all of that data in memory at once.
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