C++ template class as argument of a function

Question

There is a class library (I cannot/should not change) defined in MIDI.h:

template<class SerialPort, class _Settings = DefaultSettings>
class MidiInterface
{
      ...

I want to use this class as argument. Question question is a duplicate, however I still get a compilation error.

My own header class file looks like:

#include <MIDI.h>

class M
{
  public:
    void setup();
    void run();

  private:
    void printMessage(const MidiInterface<SerialPort, _Settings>&
          midiInterface);
};

I get the following errors:

In file included from sketch\\M.cpp:1:0:

M.h:10: error: 'MidiInterface' does not name a type

 void printMessage(const MidiInterface<SerialPort, _Settings>& midiInterface);

                         ^

M.h:10: error: expected ',' or '...' before '<' token

 void printMessage(const MidiInterface<SerialPort, _Settings>& midiInterface);

                                      ^

exit status 1
'MidiInterface' does not name a type

How can I change the code so it compiles?

Answer 1

It looks like MIDI.h in this code puts everything in a namespace. If that's what you're using, try MIDI_NAMESPACE::MidiInterface<SerialPort, _Settings> .