How to Count a record per day by day using mysql

Question

How to Count the records as per the date it self.I just pass the two dates using BETWEEN in my mysql query eg for 2017-05-01 and 2017-05-10

Table:

 tid    vid     dates       type
-------------------------------------
 1  TN01VD2365  2017-05-01  Cash
 2  TN01VD1254  2017-05-02  Cash
 3  TN03JG2589  2017-05-01  Credit
 4  TN12KL5874  2017-05-01  Cash
 5  TN14DS4569  2017-05-05  Compliment
 6  TN45KJ6987  2017-05-06  Credit
 7  TN45AS6542  2017-05-06  Cash
 8  TN78DF6589  2017-05-10  Complimant

i want the result like this

dates        typeCash       typeCredit      typeCompliment
---------------------------------------------------------------
2017-05-01       2           1             0
2017-05-02       1           0             0
2017-05-05       0           0             1
2017-05-06       1           1             0
2017-05-10       0           0             1

My try

  $json="";

    $created_date1="5-1-2017";
    $created_date2="5-10-2017";


    if(isset($created_date1))
    {
        $x=explode("-",$created_date1);
        $created_date1=$x[1]."-".$x[0]."-".$x[2];
        $created_date1 = strtotime($created_date1);
        $created_date1 = date('Y-m-d',$created_date1);  
    }
if(isset($created_date2))
{
    $y=explode("-",$created_date2);
    $created_date2=$y[1]."-".$y[0]."-".$y[2];
    $created_date2 = strtotime("$created_date2");
    $created_date2 = date('Y-m-d',$created_date2);
}
    $date2=$created_date2;
    $i=0;
    while($created_date1<=$date2)
    {
        $created_date2=$created_date1;


                $mycount = "select 
                                    count(tid) as mycount 

                                    from 

                                    third_table 

                                    where 

                                    dates BETWEEN '".$created_date1."' AND '".$created_date2."'";


                $execte=mysql_query($mycount);
                $mynum=mysql_fetch_array($execte);
                $mynum_count=$mynum['mycount'];

            if($mynum_count>0)
            {
                    $trip_per_day="select 
                                    a.eid,a.name,
                                    count(b.tid) as trips_per_day,
                                    COUNT(IF(b.type_of_trip='Credit',1,null)) as credit_trips,
                                    COUNT(IF(b.type_of_trip='Compliment',1,null)) as compliment_trips 
                                    b.dates 
                                    from third_table b 
                                    LEFT JOIN add_employees a ON b.emp_id=a.eid 
                                    where b.dates between '$created_date1' and '$created_date2' 
                                    group by b.tid";

                    $run_qry=mysql_query($trip_per_day);
                    $row = mysql_fetch_array($run_qry);
                    $name = $row['name'];
                    $trip_per_day = $row['trips_per_day'];
                    $cash_trips = $row['cash_trips'];
                    $credit_trips = $row['credit_trips'];
                    $compliment_trips = $row['compliment_trips'];

                    $arr[$i]["name"]=$name;
                    $arr[$i]["date"]=$created_date1;//particular data
                    $arr[$i]["trips_per_day"] = $trip_per_day;//for trip_per_day
                    $arr[$i]["cash_trips"] = $cash_trips;//for cash_trips
                    $arr[$i]["credit_trips"] = $credit_trips;//for credit_trips
                    $arr[$i]["compliment_trips"] = $compliment_trips;//for compliment_trips
            }
            $inc_qry="select '".$created_date1."' + INTERVAL 1 DAY";
            $query=mysql_query($inc_qry);
            while($val=mysql_fetch_array($query))
            {
                $created_date1=$val[0];
            }
            $i++;
    }
    $json['all_counts_reports']=$arr;
    $json=json_encode($json);

    $array = json_decode($json,true);
    $array['all_counts_reports']=array_values($array['all_counts_reports']);
    //var_export(json_encode($array));
    echo $result = str_replace('', '', json_encode($array));

it will give the wrong output as well as looping unstoppable.How to get Day by day count using between dates in mysql. please guide me .

Answer 1

There is no need to use php code to do the job you want, as you can get the required output using conditional aggregation in a single SQL query:

SELECT dates,
       SUM(type = 'Cash') AS typeCash,
       SUM(type = 'Credit') AS typeCredit,
       SUM(type = 'Compliment') AS typeCompliment
FROM mytable
WHERE dates BETWEEN '2017-05-01' AND '2017-05-10'
GROUP BY dates;

Demo here