I have two lists, t
and e
, of the same size: to each element t[i]
corresponds an element e[i]
. I want to print each pair t[i] e[i]
, but summing together elements e[i]
and e[i-1]
whenever the corresponding t[i]
and t[i-1]
are closer than 1. In this case, elements e[5]
and e[4]
should be summed up, since the corresponding t[5]-t[4]<1
. The point is, I want to REPLACE the 4th elements with the 4th+5th elements, without printing the 5th elements. My code is:
t = [1, 5, 10, 16, 20, 21, 28, 33, 39, 42, 45, 50, 56]
e = ['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M']
for j in range(1,12):
if t[j]-t[j-1] <= 1:
print t[j-1], e[j-1]+e[j]
else:
if t[j] > t[j-1]:
print t[j-1], e[j-1]
But this gives me:
1 A
5 B
10 C
16 D
20 EF
21 F
28 G
33 H
39 I
42 J
45 K
I don't want to print 21 F
, as it is already summed in the 20 EF
. How can I do that? Is there a way to increase the counter i
at the end of the if
condition? Thank you in advance.
Another solution is a while loop :
t = [1, 5, 10, 16, 20, 21, 28, 33, 39, 42, 45, 50, 56]
e = ['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M']
j = 1
while j < len(t):
if t[j]-t[j-1] <= 1:
print t[j-1], e[j-1]+e[j]
j += 1
else:
if t[j] > t[j-1]:
print t[j-1], e[j-1]
j += 1
If it's just about the output:
for i in range(0, len(t)):
if i<1:
print( t[i], e[i], end="")
else:
if t[i] - t[i-1] > 1:
print()
print( t[i], e[i], end="")
else:
print( e[i], end="")
prints
1 A
5 B
10 C
16 D
20 EF
28 G
33 H
39 I
42 J
45 K
50 L
56 M
Either you use the solution down here or you look at this post: Skip over a value in the range function in python
t = [1, 5, 10, 16, 20, 21, 28, 33, 39, 42, 45, 50, 56]
e = ['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M']
skip = False
for j in range(len(t)):
if not skip:
if t[j]-t[j-1] <= 1:
print t[j-1], e[j-1]+e[j]
skip = True
else:
if t[j] > t[j-1]:
print t[j-1], e[j-1]
else:
skip = False
>1 A
>5 B
>10 C
>16 D
>20 EF
>28 G
>33 H
>39 I
>42 J
>45 K
>50 L
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