How to print out a string of a '&', equal to the length of a list

Question

I want to print out a list of the character '&' as many times as there are in a given number. So if the number is 10, I want the result to be '&&&&&&&&&&&'

What I have done is turned the int into a list so I can better visualize what I want to perform.

def print_list_&(size):
    """super serious docstring"""
    result_1 = 1
    result_2 = size + 1
    result = list(range(result_1, result_2))
    return result

I'm stuck on where I go from here. This is university work so I'm better off with a push in the right direction than a straight answer.

Answer 1

'&' * 10 will give you '&&&&&&&&&&' . Therefore it seems you just need '&' * size .

Answer 2

Python 2:

N = int(raw_input())
print '&' * N

Python 3:

N = int(input())
print ('&' * N)