Parse PHP Array To Build Query String
Question
I am trying to build a multi select on my php page where a user can select what fields to query from a database. I have the multi-select set-up and I am trying to work on the "behind-the-scenese" syntax for the query build portion, but when I hit my echo statement, it is not displaying what is selected.
What would be the proper way to build out a query string based off what is selected from the multi-select on the page? (Now granted I am omitting a valid connection string etc.)
<html>
<select name="employee_data[]" multiple style="min-width: 200px;" id="user_data">
<option value="EmployeeName">Employee Name</option>
<option value="TeamName">Team Name</option>
<option value="ManagerName">Manager Name</option>
<option value="Department">Department</option>
<option value="Recruiter">Recruiter</option>
<option value="RecruitingAgency">RecrutingAgency</option>
</select>
</html>
<?php
$query = "Select employeename ";
if (in_array('TeamName')) $query .= ",teamname"
if (in_array('ManagerName')) $query .= ",ManagerName"
if (in_array('Department')) $query .= ",Department"
if (in_array('Recruiter')) $query .= ",Recruiter"
if (in_array('RecruitingAgency')) $query .= ",RecruitingAgency"
$query .= " FROM employeepersonelinfo where employeename = '$employeename'";
echo $query;
?>
1 answers
solution1
0 ACCPTED 2017-05-18 14:02:31
Below is the working PHP code. Instead of checking each, you can use implode() .
<?php
if (!isset($_POST['employee_data'])) die();
$query = "Select employeename ";
$query .= implode(', ', $_POST['employee_data']);
$query .= " FROM employeepersonelinfo where employeename = '" .
$_POST['employeename'] . "'";
echo $query;
?>
You don't really need to check each and every value. You can save lines of code and lines of conditions by using array functions.
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