PyQt5 Fill the table

Question

I need to randomly fill out the table. I did this using the for loop. But filling occurs only at the last iteration. That is, only one cell is repainted. This is a function:

def generateTable(self):
    count = random.randint(10, 20)
    item = QtWidgets.QTableWidgetItem()
    predator = QtGui.QBrush(QtGui.QColor(0, 255, 0))
    predator.setStyle(QtCore.Qt.SolidPattern)
    herbivore = QtGui.QBrush(QtGui.QColor(255, 0, 0))
    herbivore.setStyle(QtCore.Qt.SolidPattern)
    for i in range(count):
        x = random.randint(0, 19)
        y = random.randint(0, 29)
        if random.randint(0, 1) == 0:
            item.setBackground(predator)
            self.BoardTable.setItem(x, y, item)
        else:
            item.setBackground(herbivore)
            self.BoardTable.setItem(x, y, item)

I think there is not enough of an important line in the loop.

Answer 1

I had to put QTableWidgetItem in the loop:

    def generateTable(self):
    count = random.randint(10, 20)
    predator = QtGui.QBrush(QtGui.QColor(255, 0, 0))
    predator.setStyle(QtCore.Qt.SolidPattern)
    herbivore = QtGui.QBrush(QtGui.QColor(0, 255, 0))
    herbivore.setStyle(QtCore.Qt.SolidPattern)
    for i in range(count):
        item = QtWidgets.QTableWidgetItem()
        x = random.randint(0, 19)
        y = random.randint(0, 29)
        if random.randint(0, 1) == 0:
            item.setBackground(predator)
            self.BoardTable.setItem(x, y, item)
        else:
            item.setBackground(herbivore)
            self.BoardTable.setItem(x, y, item)