im building a system to sort some .log files in .txt format so that I later can send it to excel. There is 70+ files and in every file im scanning for a keyword, I get 100+ strings that I want to save in a .txt. I can get every string that I want and see from which .log file each log has ben taken, but now I want to rename the file that the .log came from with a corresponding number (one number for every file). I have tried counting loops, array and strings but I wont get I right....
import glob
import os
import itertools
def LogFile(filename, tester):
message = []
data = []
with open(filename) as filesearch: # open search file
filesearch = filesearch.readlines() # read file
file = filename[39:]
for line in filesearch:
if tester in line: # extract ""
start = '-> '
end = ':\ '
number = line[line.find(start)+3: line.find(end)] #[ord('-> '):ord(' :\ ')]
data.append(number) # store all found wors in array
text = line[line.find(end)+3:]
message.append(text)
with open('Msg.txt', 'a') as handler: # create .txt file
for i in range(len(data)):
handler.write(f"{file}|{data[i]}|{message[i]}")
# open with 'w' to "reset" the file.
with open('Msg.txt', 'w') as file_handler:
pass
# ---------------------------------------------------------------------------------
for filename in glob.glob(r'C:\Users\\Desktop\Access\*.log'):
LogFile(filename, 'Sending Request: Tester')
How its now
from .txt file
GTX77_ 2017-05-20_1209.log|166 9 02 F
GTX77_ 2017-08-24_1209.log|166 9 03 F
JBB 925_1720_1400.log|161 9 02 F
JBB 925_1724_1900.log|161 9 12 F
How I want it
new .txt file
1|166 9 02 F
1|166 9 03 F
2|161 9 02 F
2|161 9 12 F
So my question is if there is some function that can change the variable "filename" to a corresponding number instead (ex, all .log files from file GTX77.log gets index 1 instead, and all .log from JBB925 gets index 2...)
You can use a dictionary for that. you initialize it for every filename then you can recover the index with get(filename, default_value)
i=1
d = {}
for filename in filenames:
if not d.get(filename, False):
d[filename] = i
i+=1
The technical post webpages of this site follow the CC BY-SA 4.0 protocol. If you need to reprint, please indicate the site URL or the original address.Any question please contact:yoyou2525@163.com.