Unpack a two-dimensional list through the loop

Question

I have a need of unpacking two-dimensional list (list of lists) with a dynamic length. The whole task is to form a full-featured HTML-table from my list with the help of lxml framework.

Having been used this excellent answer as a backbone I came to the following code for my task:

 page = (
    E.html(
        E.body(
        E.table(
                E.tr(
                    E.th(E.div("header1")),
                      ...
                    E.th(E.div("header40")),
                    ),
                *[E.tr(
                     *[
                        E.td(str(col)) for col in p_list[1] <<- how to put N here???
                     ]
                    ) for row in range(len(p_list))]
                , border="2"
                )
            )
        )
    )

The first E.tr is a header for my table, the second one *[E.tr is unpacked from the list p_list . The list has N elements (aka rows) each of which is a list itself consisting of around 50 elements (aka columns of N row).

The p_list is declared and filled like this:

p_list = list()
rows = table.iter('div')
p_list.append([c.text for c in rows])
rows = table.xpath("body/table")[0].findall("tr")
for row in rows[2:]:
   p_list.append([c.text for c in row.getchildren()])

Now this code can only output the same row of p_list N times and works only with a hard-coded row number, but what if I want to specify it dynamically to output the whole table?

Cannot figure out how to do this.

Answer 1

Replace p_list[1] with p_list[row] . Even better, don't use range :

*[E.tr(
   *[ E.td(str(col)) for col in row ]
) for row in p_list ]