I have use a 428×1 cell array called data
data = {[1×1 struct]
[1×1 struct]
....
[1x1 struct]}
These struct all have the same structure
data {2,1}
>>struct with fields
additional_model_information: 'H Series,S3150-S0-AW-04-02-C-F421,'
ceiling_fan_size_diameters_in_inches: '60'
airflow_efficiency_cfm_watt_low: '727'
airflow_efficiency_cfm_watt_high: '392'
The structure fields are the same for all 428 cells, and the fields values change in each struct.
How could i create a table that puts all of the structs together so that it shows all of the field values for each field? Pehaps using a nested for loop?
I eventually want to export this data to excel.
How about
T = cell(length(data) , 4);
for k = 1 : length(data)
T(k , :) = {data{k}.additional_model_information , ...
data{k}.ceiling_fan_size_diameters_in_inches, ...
data{k}.airflow_efficiency_cfm_watt_low, ...
data{k}.airflow_efficiency_cfm_watt_high};
end
Then you can use xlswrite
to export to excel.
Let's say you've got your nx1 cell array of structs, data
. This method doesn't assume you have 4 fields in your data or any knowledge of what they are called. You could even use it with structs with different fieldnames if you included some try
/ catch
logic.
You can get the field names of a representative struct using fieldnames
fnames = fieldnames(data{1});
Then set up some output cell array out
of the correct size
out = cell(numel(fnames), numel(data));
Then use nested loops to 1. loop through items in data
and 2. loop through field names.
for n = 1:numel(data)
for field = 1:numel(fnames)
temp = data{n};
out{field, n} = temp.(fnames{field});
end
end
Finally, append the field names as the first column
out = [fnames, out];
And write the cell array to your Excel file
% File location, cell array, sheet, cell
xlswrite('C:\...\test.xlsx', out, 1, 'A1');
The technical post webpages of this site follow the CC BY-SA 4.0 protocol. If you need to reprint, please indicate the site URL or the original address.Any question please contact:yoyou2525@163.com.