Total Sum SQL Server

Question

I have a query that collects many different columns, and I want to include a column that sums the price of every component in an order. Right now, I already have a column that simply shows the price of every component of an order, but I am not sure how to create this new column.

I would think that the code would go something like this, but I am not really clear on what an aggregate function is or why I get an error regarding the aggregate function when I try to run this code.

SELECT ID, Location, Price, (SUM(PriceDescription) FROM table GROUP BY ID WHERE PriceDescription LIKE 'Cost.%' AS Summary) FROM table

When I say each component, I mean that every ID I have has many different items that make up the general price. I only want to find out how much money I spend on my supplies that I need for my pressure washers which is why I said `Where PriceDescription LIKE 'Cost.%'

To further explain, I have receipts of every customer I've worked with and in these receipts I write down my cost for the soap that I use and the tools for the pressure washer that I rent. I label all of these with 'Cost.' so it looks like (Cost.Water), (Cost.Soap), (Cost.Gas), (Cost.Tools) and I would like it so for Order 1 it there's a column that sums all the Cost. _ prices for the order and for Order 2 it sums all the Cost._ prices for that order. I should also mention that each Order does not have the same number of Costs (sometimes when I use my power washer I might not have to buy gas and occasionally soap).

I hope this makes sense, if not please let me know how I can explain further.

`ID    Location    Price     PriceDescription
 1     Park        10        Cost.Water
 1     Park        8         Cost.Gas
 1     Park        11        Cost.Soap
 2     Tom         20        Cost.Water
 2     Tom         6         Cost.Soap
 3     Matt        15        Cost.Tools
 3     Matt        15        Cost.Gas
 3     Matt        21        Cost.Tools
 4     College     32        Cost.Gas
 4     College     22        Cost.Water
 4     College     11        Cost.Tools`

I would like for my query to create a column like such

`ID    Location    Price    Summary
 1     Park        10       29
 1     Park        8        
 1     Park        11       
 2     Tom         20       26
 2     Tom         6        
 3     Matt        15       51
 3     Matt        15       
 3     Matt        21       
 4     College     32       65
 4     College     22       
 4     College     11        `

But if the 'Summary' was printed on every line instead of just at the top one, that would be okay too.

Answer 1

You just require sum(Price) over(Partition by Location) will give total sum as below:

SELECT ID, Location, Price, SUM(Price) over(Partition by Location) AS Summed_Price
   FROM yourtable
WHERE PriceDescription LIKE 'Cost.%' 

Answer 2

First, if your Price column really contains values that match 'Cost.%' , then you can not apply SUM() over it. SUM() expects a number (eg INT, FLOAT, REAL or DECIMAL). If it is text then you need to explicitly convert it to a number by adding a CAST or CONVERT clause inside the SUM() call.

Second, your query syntax is wrong: you need GROUP BY, and the SELECT fields are not specified correctly. And you want to SUM() the Price field, not the PriceDescription field (which you can't even sum as I explained)

Assuming that Price is numeric (see my first remark), then this is how it can be done:

SELECT ID
     , Location
     , Price
     , (SELECT SUM(Price)
        FROM table
        WHERE ID = T1.ID AND Location = T1.Location
       ) AS Summed_Price
FROM table AS T1

Answer 3

to get exact result like posted in question

    Select  
                T.ID,
                T.Location,
                T.Price,
                CASE WHEN (R) = 1 then RN ELSE NULL  END Summary 
            from  (
    select 
                ID, 
                Location, 
                Price ,
                SUM(Price)OVER(PARTITION BY Location)RN,
                ROW_number()OVER(PARTITION BY Location ORDER BY ID )R 
            from  Table
     )T
order by T.ID