#include<iostream>
using namespace std;
class stack
{
int size=10;
int stack[size]={0}, value=0, top;
top=size;
public:
void push(int v)
{
if(top==0)
cout<<"\nstack is full\n";
else
{--top;
stack[top]=v;}
}
void pop()
{
if(top==size)
cout<<"\nstack is empty\n";
else
{top++;
stack[top];
stack[top-1]=0;
}
}
void display()
{
if(top==size)
cout<<"\nstack empty\n";
else
{
for(int i=top;i<size-1;i++)
{
cout<<stack[i];
}
}
}
};
int main()
{
stack s;
char t;
int value,ch;
do
{
cout<<"\n1.push\n";
cout<<"\n2.pop\n";
cout<<"\n3.display\n";
cout<<"enter choice:\n";
cin>>ch;
switch(ch)
{
case 1:cout<<"\nenter the value to be pushed\n";
cin>>value;
s.push(value);
break;
case 2:s.pop();
break;
case 3:s.display();
break;
default:
cout<<"\nwrong choice\n";
}
cout<<"\ndo u want to retry\n";
cin>>t;
}while(t=='y' || t=='Y');
return 0;
}
Simplest fix to errors occurring is changing int size=10;
to static const int size=10;
. After this, apart from occurring warning with stack[top];
being empty statement, there is logical error in display
loop in for(int i=top;i<size-1;i++)
where it should be either for(int i=top;i<size;i++)
or for(int i=top;i<=size-1;i++)
.
As answered by Tomáš Zahradníček, you need to fix a few things to have your code compile (using -std=c++11).
I used for(int i=top; i<size; ++i)
in the display
method. I also add that your pop
method could simply do top++;
without overwriting the stack.
Anyways, regarding your problem of nothing being printed on cout : you obviously tried with 1 item pushed in the stack, but not with 2, which would have pointed to faulty line (the for
loop).
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