How do you write a regex in python which picks out all strings beginning with a specific number

Question

I'm trying to get this regex to pick out both 7gh and 7ui but I can only get it to pick out the first one. If anyone knows how to amend the regex such that it also picks out 7ui, I would seriously appreciate it. I should also point out that I mean strings separated by a space.

b = re.search(r'^7\w+','7gh ghj 7ui')
c = b.group()

Answer 1

Remove ^ and use findall() :

>>> re.findall(r'7\w+','7gh ghj 7ui')
['7gh', '7ui']

Answer 2

You need to remove ^ (start of string anchor) and use re.findall to find all non-overlapping matches of pattern in string :

import re
res = re.findall(r'7\w+','7gh ghj 7ui')
print(res)

See the Python demo

If you need to get these substrings as whole words , enclose the pattern with a word boundary, \\b :

res = re.findall(r'\b7\w+\b','7gh ghj 7ui')

Answer 3

您可能会发现不使用正则表达式会更容易

[s for s in my_string.split() if s.startswith('7')]