SQL Server - Get First rows matching date criteria

Question

I have a table like this:

 ID   DateValue       Amount
 -----------------------------
 1    2017/08/09      217 
 1    2017/08/08      204    
 1    2017/08/07      322    
 2    2017/08/09      1543    
 2    2017/08/08      1285    
 3    2017/08/09      12 
 4    2017/08/09      347

I only want to obtain the first rows for the most recent "DateValue" value. Like this:

 ID   DateValue       Amount
 -----------------------------
 1    2017/08/09      217 
 2    2017/08/09      1543    
 3    2017/08/09      12 
 4    2017/08/09      347

I thought of using the "MAX" method like this:

SELECT ID, MAX(DateValue), MAX(Amount) FROM [dbo].[MyTable] GROUP BY Id

But for the ID 1, I get 322 while I should have 217 (the most recent value)

Is there a simple way to accomplish what I need?

Answer 1

You can use the WITH TIES clause.

Select Top 1 with ties *
 From  YourTable
 Order By Row_Number() over (Partition By Id Order By DateValue Desc)

Returns

Answer 2

This also work ,

  select ID,DateValue,Amount from 
(select ID,DateValue,Amount,ROW_NUMBER() over
 (partition by ID order by DateValue Desc)  RowNumber  
from [dbo].[MyTable]) x
where RowNumber=1