Bash run script from script using variable

Question

I am trying to run bash script from bash script using variable.

The variable is assigned before from parsed CSV, and when I echo it the path to another script looks ok. When I try to run the script path from the variable it fails.

Assiging the variable (2nd column from csv):

THE_VARIABLE=`echo ${CHOICE[${WHICH}]} | awk -F";" '{print $2}'`

echo $THE_VARIABLE (ok):

/fake_path/scripts/test.sh

Bash debug:

    + echo $'/fake_path/scripts/test.sh\r'

However after that when trying to run:

bash $THE_VARIABLE
: No such file or directoryripts/test.sh

It seems like taking only part of the string in variable(?).

Thanks for help!

Answer 1

The string ends with ASCII character 13 (\\x0D or \\015 or \\r) and not the sequence '\\' 'r' , with echo the trailing \\r can't be seen because echo adds a \\n , but appending a # character for example will show at begining of line.

echo "${THE_VARIABLE}#"
#fake_path/scripts/test.sh

to remove the trailing \\r :

THE_VARIABLE=${THE_VARIABLE%$'\r'}

otherwise it means that input file has dos line ending \\r\\n , it could be modified with dos2unix .