Let's say I have a list datalist
, with len(datalist) = 4
. Let's say I want each of the elements in the list to be represented in a string in this way:
s = "'{0}'::'{1}'::'{2}' '{3}'\n".format(datalist[0], datalist[1], datalist[2], datalist[3])
I don't like having to type datalist[index]
so many times, and feel like there should be a more effective way. I tried:
s = "'{0}'::'{1}'::'{2}' '{3}'\n".format(datalist[i] for i in range(4))
But this doesn't work:
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
IndexError: tuple index out of range
Does anybody know a functioning way to achieve this efficiently and concisely?
Yes, use argument unpacking with the "splat" operator *
:
>>> s = "'{0}'::'{1}'::'{2}' '{3}'\n"
>>> datalist = ['foo','bar','baz','fizz']
>>> s.format(*datalist)
"'foo'::'bar'::'baz' 'fizz'\n"
>>>
>>> "'{0[0]}'::'{0[1]}'::'{0[2]}' '{0[3]}'\\n".format(datalist) "'foo'::'bar'::'baz' 'fizz'\\n"
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