Is there shortcut to initialize fixed size array with constants. For examle, it I need int array[300]
with 10 in each of 300 spaces, is there trick to avoid writinig 10 300 times?
Here's a compile time solution that uses initialisation (uses std::array
instead of a C array):
template<std::size_t N, typename T, std::size_t... Is>
constexpr std::array<T, N> make_filled_array(
std::index_sequence<Is...>,
T const& value
)
{
return {((void)Is, value)...};
}
template<std::size_t N, typename T>
constexpr std::array<T, N> make_filled_array(T const& value)
{
return make_filled_array<N>(std::make_index_sequence<N>(), value);
}
auto xs = make_filled_array<300, int>(10);
auto ys = make_filled_array<300>(10);
You can use std::fill_n
:
int array[300] = {0}; // initialise the array with all 0's
std::fill_n(array, 300, 10); // fill the array with 10's
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