I am using python 2.7. I need to truncate a binary number from a x-bits to 8 bits (byte) i will write an example of what i would like to do to make it clear and also because stackexchange doesn't leave me write my question for some reason, example:
0b1010101010100101 -> 0b10100101
i tried this workaround: converting it to string and then cutting it as a sub-string, but i didn't manage to make it working
str_cs = str(bin(cs))
str_cs = str_cs[to_cut:]
but i am facing many problem to convert it back to a binary number... how would you truncate it?
Simply use a bitwise &
with a byte of all 1
s:
cs = cs & 0b11111111
# or, if you're feeling daring:
cs &= 0b11111111
Solution of Phydeaux much better but I was doing :
>>> cs=0b1010101010100101
>>> cs=int(bin(cs)[-8:], 2)
>>> bin(cs)
'0b10100101'
Based on what you were trying with str
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