Why is this giving me:
"TypeError: argument of type 'int' is not iterable"
when I converted the list to strings:
def giveMeFive (start, end):
numbers = list(range(start,end))
for x in numbers:
[str(x) for x in numbers]
if str(5) in x:
return x
u can use this code
def giveMeFive (start, end):
numbers = list(range(start,end))
return numbers.index(5)
When you write [str(x) for x in numbers]
all by itself, you are creating a new list of strings, and then immediately throwing it away. You have to save it in a variable to keep it.
Try
def giveMeFive (start, end):
numbers = list(range(start,end))
strings = [str(x) for x in numbers]
for x in strings:
if str(5) in x:
return x
Now, there are more errors in your code, but hopefully this will get you unstuck.
更清楚地说,此代码旨在返回包含字符串“5”的特定范围内的所有数字。
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