I need your helps about assigning value to external variable inside awk command.Please check the following script
interfaceName=$1
exitStatus=0
ip -o link show | awk '{ if($2=="'$interfaceName'") $exitStatus=1}'
if(exitStatus==0) then
exit 0
else
exit 1
fi
The script takes network interface name as argument then check the available interfaces which match with the taken. if find matched interface it, exits with 1 else with 0.The problem is that i cannot change the external variable exitStatus inside awk in the following line
awk '{ if($2=="'$interfaceName'") $exitStatus=1}'
How to assign value to it in awk ?
You can make awk return an exit status to the shell:
ip -o link show | awk '{ if($2=="'$interfaceName'") exit 1}'
if [ $? -eq 1 ]; then
# TODO
The technical post webpages of this site follow the CC BY-SA 4.0 protocol. If you need to reprint, please indicate the site URL or the original address.Any question please contact:yoyou2525@163.com.