C how to convert string of unsigned long long to uint32_t[]?

Question

是否有任何短代码将 unsigned long long 字符串转换为 uint32_t[]？

eg, 11767989860 => uint32_t[] {0xaaaa, 0xbbbb}?

Answer 1

Ignoring overflow, this gives you an unsigned long long (which I believe is 64-bit, not 32):

unsigned long long r = 0;
while (*pstr >= '0' && *pstr <= '9') r = r * 10 + (*pstr++ - '0');

Answer 2

You have 11767989860 but in string form, and you want it to break into integer array {0x2,0xBD6D4664} .

You can first convert string to long long, then copy 4 bytes from that long long variable into your integer array.

Below is the sample program

#include<stdio.h>
#include<stdint.h>
int main()
{
unsigned long long ll = 0;
uint32_t arr[2];
char str[]="11767989860";
char *tmpPtr = NULL;
tmpPtr = &ll;

sscanf(str,"%llu",&ll);
printf("ll=%llu",ll);

/*Big endian*/
memcpy(arr,&ll,sizeof(ll));
printf("\n%u %u\n",arr[0],arr[1]);
/*Little endian*/
memcpy(&arr,&tmpPtr[4],sizeof(ll)/2);
memcpy(&arr[1],&tmpPtr[0],sizeof(ll)/2);
printf("\n%u %u\n",arr[0],arr[1]);

return 0;
}