I have a text file which consists of many lines of text.
I would like to replace only the first line of a text file using python v3.6 regardless of the contents. I do not need to do a line-by-line search and replace the line accordingly. No duplication with question Search and replace a line in a file in Python
Here is my code;
import fileinput
file = open("test.txt", "r+")
file.seek(0)
file.write("My first line")
file.close()
The code works partially. If the original first line has string longer than "My first line"
, the excess sub-string still remains. To be clearer, if original line is "XXXXXXXXXXXXXXXXXXXXXXXXX"
, then the output will be "My first lineXXXXXXXXXXXXXX"
. I want the output to be only "My first line"
. Is there a better way to implement the code?
You can use the readlines and writelines to do this. For example, I created a file called "test.txt" that contains two lines (in Out[3]). After opening the file, I can use f.readlines() to get all lines in a list of string format. Then, the only thing I need to do is to replace the first element of the string to whatever I want, and then write back.
with open("test.txt") as f:
lines = f.readlines()
lines # ['This is the first line.\n', 'This is the second line.\n']
lines[0] = "This is the line that's replaced.\n"
lines # ["This is the line that's replaced.\n", 'This is the second line.\n']
with open("test.txt", "w") as f:
f.writelines(lines)
Reading and writing content to the file is already answered by @Zhang.
I am just giving the answer for efficiency instead of reading all the lines.
Use: shutil.copyfileobj
from_file.readline() # and discard
to_file.write(replacement_line)
shutil.copyfileobj(from_file, to_file)
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