I have a log file like this one with different start and end marks:
#Wiliam
#Arthur
#Jackie
high;
10 11 11;
#Jim
#Jill
#Catherine
#Abby
low;
girl;
10 11 11 11;
#Ablett
#Adelina
none;
5,8;
I need to parse it line by line to get the result as below:
[
['#Wiliam','#Arthur','#Jackie','high;','10 11 11;'],
['#Jim','#Jill','#Catherine','#Abby','low;','girl;','10 11 11 11;'],
['#Ablett','#Adelina','none;','5,8;']
]
Is there a solution?
It's understood that each sublist starts with #
and ends with ;
. This is exactly what this Pythonic generator implementation uses:
def read_lists():
with open('data') as file:
sublist = []
previous_line = ''
for line in file:
line = line.strip()
if line.startswith('#') and previous_line.endswith(';'):
yield sublist
sublist = []
sublist.append(line)
previous_line = line
yield sublist
for sublist in read_lists():
print(sublist)
['#Wiliam', '#Arthur', '#Jackie', 'high;', '10 11 11;']
['#Jim', '#Jill', '#Catherine', '#Abby', 'low;', 'girl;', '10 11 11 11;']
['#Ablett', '#Adelina', 'none;', '5,8;']
In order to parse the file – you need to find the pattern , which will lead you to successful data collection.
From your example, – I can see that you stop appending items in sublist when you read string with integers and semicolon. I'd try to do it this way:
import ast
result = []
with open(f,'rb') as fl:
sublist = []
for line in fl:
line = line.strip()
sublist.append(line)
if type(ast.literal_eval(line[0])) is int and line[-1] == ';':
result.append(sublist)
sublist = []
Here's my implementation. Not entirely sure what the is_terminator() logic should look like.
def is_terminator(tokens):
"""
Return True if tokens is a terminator.
"""
is_token_terminator = False
tokens = tokens.split()
if len(tokens) > 0:
token = tokens[-1]
if token.endswith(";"):
try:
int(token[:-1])
except ValueError:
pass # not an int.. and so not a terminator?
else:
is_token_terminator = True
return is_token_terminator
sublist = []
result = [sublist, ]
f = file("input.txt", "r")
for tokens in f.readlines():
sublist.append(tokens)
if is_terminator(tokens):
sublist = []
result.append(sublist)
print result
This appends the lines to a sub-list until it reaches a point where the previous appended line ends with a semicolon but the current line does not. At that point, it creates a new sub-list and continues.
lst = [[]]
try:
with open("log.log", "r") as f:
i = 0 # Index of the sub-list
for line in f:
line = line.strip()
if line[-1:] != ";" and lst[i] and lst[i][-1][-1:] == ";":
i += 1 # Increment the sub-list index.
lst.append([]) # Append a new empty sub-list.
lst[i].append(line)
except FileNotFoundError:
print("File does not exist.")
print(lst)
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