Test if JavaScript string contains all of multiple values, in any order, and case-insensitive

Question

I want to perform what should be a simple search on a string to see if it contains all of several search terms, in a case insensitive manner.

For example, "The quick brown fox" contains the words "fox" and "quick", so I want a function which can take those two words and show that the phrase contains them both, regardless of their order.

So I guess what I'm asking for is a string-based "AND" search.

Answer 1

A simple solution is to use the array.every() method to check that every search term is included in a string.

I'm specifying the search terms as a single string, which will be split by spaces:

var haystackString = "The quick brown fox";
var needleString   = "fox quick";

var searchTerms = needleString.split(" ");

return searchTerms.every(function stringContains(element, index, array) {
    return haystackString.toUpperCase().includes(element.toUpperCase());
});

The above will return true .

Be aware that toUpperCase() might not work with all languages.

Answer 2

Convert the array of terms to a RegExp . Then use use String#match to find all matches in string. If the number of matches is identical to the number of terms, it contains all of them:

 var str = 'The quick brown fox'; function containsAll(str, terms) { var regexp = new RegExp(`\\\\b(${terms.join('|')})\\\\b`, 'gi'); var matches = str.match(regexp); return matches !== null && matches.length === terms.length; } console.log(containsAll(str, ['fox', 'quick'])); console.log(containsAll(str, ['cat', 'quick']));