I tried to remove the third and the fourth list from the list of list in python.
My list of list is below:
List = [
['101', 'Dashboard', '1', '1'],
['102', 'Potential Cstomer', '1', '1'],
['102-01', 'Potential Cstomer', '1', '1'],
['102-02', 'Potential Cstomer Activity', '1', '1']
]
After remove the third and fourth element of list, I would like to be like this:
NewList = [
['101', 'Dashboard'],
['102', 'Potential Cstomer'],
['102-01', 'Potential Cstomer'],
['102-02', 'Potential Customer Activity']
]
I tried my code like below but it did not make any change.
NewList = [list(element) for element in List if element[0] or element[1]]
print NewList
How should I change my current code to achieve my expected result? Thanks.
Slice each nested list in a list comprehension . The slice notation starts at index 0 and stops at 1 ie [0, 2)
:
NewList = [element[:2] for element in List]
When the start index is not specified, it is taken as None
which is the same as start index of the list when None
appears before the first :
.
Same as:
NewList = [element[slice(None, 2)] for element in List] # More verbose
In Python 3, you could use extended unpacking to achieve the same thing applying the 'splat' operator *
:
NewList = [elements for *elements, _, _ in List]
How about this:
for s in List:
del s[3]
del s[2]
That deletes in place.
This solution uses negative indexing to allow for arbitrary length sublists, along as the original condition of two trailing digits is maintained.
List = [
['101', 'Dashboard', '1', '1'],
['102', 'Potential Cstomer', '1', '1'],
['102-01', 'Potential Cstomer', '1', '1'],
['102-02', 'Potential Cstomer Activity', '1', '1']
]
new_final_list = [i[:-2] for i in List]
for i in new_final_list:
print(i)
Output:
['101', 'Dashboard'],
['102', 'Potential Cstomer']
['102-01', 'Potential Cstomer']
['102-02', 'Potential Cstomer Activity']
Names = [["Tom", 32, 12], ["John", 54, 16], ["James", 52, 15]]
Names_new = []
for i in Names:
# print(i + )
del i[0]
Names_new.append(i)
print(Names_new)
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