regex look ahead operator

Question

I have a string consisting of N- length of special character delimiters, Input: --1-----3--1-2 where once the .split method applied on the pattern should give output as below.

I wish to make a pattern where if the length of delimiter,N is N>1, to get the resulting match as, Output: 1,3,1,-2

Note the last element.

So far I have implemented the use of look ahead operator: (\\W)(?=[\\-{2,}\\d]) giving 1,3,1,2 .

Any feedback is appreciated. Many thanks.

Answer 1

How about: (\\W){2,}

That will give you 131-2 on your input.

https://regex101.com/r/algIJ7/1