I want the number of an array with odd occurrences.
This is my code. I think it is working but I cannot output the expected number 2 as a string. I got
System.Linq.Lookup`2+Grouping[System.Int32,System.Int32]
instead.
int[] array = { 0, 0, 1, 1, 2 };
var result = array.GroupBy(a => a)
.Select(o => o)
.Where(o => (o.Count() % 2 == 1))
.FirstOrDefault();
Console.WriteLine(result.ToString());
Try this:
var result = array.GroupBy(a => a)
.Where(o => o.Count() % 2 == 1)
.FirstOrDefault().Key;
Your approach to solving the problem is wrong, the grouped values are instances of Grouping
so you have to select the appropriate values by the key.
int[] array = { 0, 0, 1, 1, 2 };
var result = array.GroupBy(a => a)
.Where(o => (o.Count() % 2 == 1))
.Select(o => o.Key);
string resultString = string.Join(", ", result.ToArray());
Console.WriteLine(resultString);
So, in this example, you should have two as the return value.
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