Why does this python code tell me permission is denied?

Question

import subprocess
subprocess.call(" python script2.py 1", shell=True)

This code does not work. It tells me permission is denied on python. Any fixes?

Answer 1

I don't know if you are doing this in bash terminal but if you are you must give yourself rights to the .py file. So type this

chmod +x script2.py

Then the terminal will give you permission to it

Answer 2

Suggestions For Using Subprocess.call()

When shell=True is dangerous?

If we execute shell commands that might include unsanitized input from an untrusted source, it will make a program vulnerable to shell injection, a serious security flaw which can result in arbitrary command execution. For this reason, the use of shell=True is strongly discouraged in cases where the command string is constructed from external input

Reference : When to use Shell=True for Python subprocess module

import subprocess
subprocess.call(" python script2.py 1", shell=True)

Try avoid shell=True in subprocess. Instead use

import subprocess
subprocess.call(['python','script2.py','1'])

Pass every thing as a list , avoid shell=True

import subprocess
subprocess.call('python script2.py 1'.split())

'python script2.py 1'.split() will create a list like ['python','script2.py', '1']

Addressing Permission Issue

Add execution permission to your script.

chmod +x script2.py