Get words from first line until first space and without first character in python

Question

I have a textfile where I want to extract the first word, but without the first character and put it into a list. Is there a way in python to do this without using regex? A text example of what I have looks like:

#blabla sjhdiod jszncoied

Where I want the first word in this case blabla without the #. If regex is the only choice, then how will the regex look like?

Answer 1

This should do the trick:

l = []
for line in open('file'):
    l.append(line.split()[0][1:])

Edit: If you have empty lines, this will throw an error. You will have to check for empty lines. Here is a possible solution:

l = []
for line in open('file'):
    if line.strip():
        l.append(line.split()[0][1:])

Answer 2

Python方式：

my_list = [line.split(' ', 1)[0][1:] for line in open('file') if line.startswith('#')]

Answer 3

a textfile where I want to extract the first word , but without the first character and put it into a list

result = []
with open('file.txt', 'r') as f:
    l = next(f).strip()    # getting the 1st line
    result.append(l[1:l.find(' ')])
print(result)

The output:

['blabla']

Answer 4

Simple enough if your input is so regular:

s = "#blabla sjhdiod jszncoied"
s.split()[0].strip('#')
blabla

split splits on whitespace by default. Take the first token and strip away '#' .