A solution of A*x = b
can be obtained by x = A\\b
. But I did x = b\\A
as I did not look for exact syntax. I got different vectors x
in with A\\b
and b\\A
. I understood that A\\b
is more or less equivalent to inv(A)*b
, but I don't understand what exactly is happening if I do b\\A
. Does anyone know about it?
From the MATLAB documentation:
If A is a rectangular m-by-n matrix with m ~= n, and B is a matrix with m rows, then A\\B returns a least-squares solution to the system of equations A*x= B.
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