How to display a countdown on a single line in the console?

Question

I need a countdown timer in python but without skipping line.

from time import sleep

for c in range (4,0,-1):
   print(c)
   sleep(1)

this code makes the countdown by jumping the lines ex:

print('3')
print('2')
print('1')

I need that in the same line show first 3, then 2, last 1. ex:

print('3,' + sleep(1) + '2,' + sleep(1) + '1.')

Answer 1

If you want delete previous number in console, you can do like

from time import sleep
import os

for i in range(4, 0, -1):
    os.system("cls")
    print(i)
    sleep(1)

this.

or you can use end parameter in print function.

from time import sleep

for i in range(4, 0, -1):
    print(i, end = '\r')
    sleep(1)

like this.

Answer 2

from time import sleep

for i in range(4, 0, -1):
    print(i, end = ' \r')
    sleep(1)

Note the space before '\r'.

When counting down from 10 to 9, 90 is displayed instead of 9 or from 100 to 99, 990 is displayed instead of 99 when no space is added before '\r'.

Adding space before '\r' prevents the extra digit from being displayed.