This is my code for appending to the 2D array and displaying it line by line into a grid.
void map_print() {
char map[head->xdim][head->ydim]; // Generate 2D array for map
memset( map, 0, sizeof(map));
FEATURE *temp=head->next; // Get the pointer of the head of linked list
while(temp!=NULL) // Generated the map with the features
{
for (int xdim = 0; xdim < temp->xdim; xdim++){
map[temp->yloc][temp->xloc + xdim] = temp->type;
printf("X axis: Appeding to map[%d][%d]\n",temp->yloc,temp->xloc+xdim);
}
for (int ydim = 0; ydim < temp->ydim; ydim++){
map[temp->yloc + ydim][temp->xloc] = temp->type;
printf("Y axis: Appeding to map[%d][%d]\n",temp->yloc + ydim,temp->xloc);
}
temp=temp->next;
}
for (int i = 0; i < head->ydim; i++) { // Print out the map
for (int j = 0; j < head->xdim; j++) {
//printf("%c ", map[i][j]);
printf("map[%d][%d](%c)",i,j,map[i][j]);
}
printf("\n");
}
}
Based on the printf, it should only append to the following coordinates. However, map(1)(4),map(2)(4),map(3)(4),map(4)(4) are printing * which i had not appended to it.
I cant find any line of my code that is adding that extra character
You mixed x and y. The declaration is char map[head->xdim][head->ydim];
( [x][y]
), but you are using it like map[temp->yloc][temp->xloc + xdim] = temp->type;
( [y][x]
).
If your array's size is [10][5]
and you are accessing [0][9]
it would invoke undefined behaviour (because of out of bounds access) and one possibility is that it would access [1][4]
(the tenth element in the 2D array) instead.
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