Calling a function multiple times consecutively with different arguments in Python (3.x)?

Question

I have a piece of code that looks like this:

myfunction(a, b, c)
myfunction(d, e, f)
myfunction(g, h, i)
myfunction(j, k, l)

The number of arguments do not change, but the function has to be called consecutively with different values each time. These values are not automatically generated and are manually inputted. Is there an inline solution to do this without creating a function to call this function? Something like:

myfunction(a, b, c)(d, e f)(g, h, i)(j, k, l)

Any help appreciated. Thanks in advance!

Answer 1

Simple, use tuple unpacking

tripples = [('a', 'b', 'c'), ('d', 'e', 'f'), ('g', 'h', 'i'), ('j', 'k', 'm')]
for tripple in tripples:
    print(myfunction(*tripple))

Answer 2

I'm surprised that nobody mentioned map

map(func, iter)

It maps each iterable in iter to the func passed in the first argument.

For your use case it should look like

map(myfunction, *zip((a, b, c), (d, e, f), (g, h, i), (j, k, l)))

Answer 3

Hi I am not sure whether it's the most pythonic way , but if you have arguments defined as in a list the you can call the function in a loop, and remove the n argument from the beginning of the list :

Have a look to the sample code :

def myfunction(x1,x2,x3):
    return x1+x2+x3


arglist = [1,2,3,4,5,6,7,8,9]
for _ in range(3):
    print  myfunction(arglist[_+0],arglist[_+1],arglist[_+2])
    # remove used arguments from the list 
    arglist= arglist[2:] 

Answer 4

你可以在这里滥用列表理解

[myfunction(*item) for item in ((a, b, c), (d, e, f), (g, h, i), (j, k, l))]

Answer 5

我想你想做的是这样的......

myfunction(myfunction(d, e, f), myfunction(g, h, i), myfunction(j, k, l))