I´m trying to open a file named the same as a bar code but I get the error that the file cannot be found?
I use this line to read the file:
string[] DxfFile = System.IO.File.ReadAllLines(textBoxBarCodeScanner.Text);
It works fine and open the file correctly if I assign the text box with:
textBoxBarCodeScanner.Text = (@"PLANKA.DXF");
I use these lines to read from the serial port:
RecievedData = RecievedData.Replace("\r\n", "").Replace("\r", "").Replace("\n", "");
textBoxBarCodeScanner.Text = (@RecievedData);
I had to remove /r first but it did not help. I´m kind a beginner so I´m not so good at finding the right debug information for you so here is what I got and please tell me where I found more useful information. If I break at the exection and look at "locals" I have a row that says text, and there I got "PLANKA.DFX" which seem to be correct.
Debug error message is as follow:
Additional information: Could not find file E:\\Win7\\Google Drive\\Visual Studio 2013 Projects\\Husmaskin GUI\\Husmaskin GUI\\bin\\Debug\\PLANKA.DFX.
This works (@"PLANKA.DXF"):
This does not (@RecievedData)??
In your screenshots, you have two different values for the file extension: DXF
and DFX
.
There may be extra whitespace around the incoming text, so I would suggest also adding .Trim()
to your code.
I would also suggest checking for the file in your code and creating an error message that is more useful to you:
var filename = txtFoo.Text;
if (!File.Exists(filename))
throw new Exception($"Could not find file '{filename}'");
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