It is possible to get webservice description by checking ?wsdl link of a service.
For example:
somewebsite.com/myservice.svc?wsdl
Is it possible to get a discription of a method by going to wsdl link of a method?
for example:
somewebsite.com/myservice.svc/Method?wsdl
原来在.svc方法的末尾添加?wsdl不会提供XML
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