How to create single json object from three different json object

Question

I want to create single JSON object from three different JSON object eg

Three variable containing JSON value :

1. GTX_INNER_JOIN 2. GTX_LEFT_OUTER_JOIN 3. GTX_RIGHT_OUTER_JOIN

all of them have same (key,value) pair. I want single JSON containing value from all of them.

I have tried angularJS and tried Angular: Copy , Extend and Merge but i didnt get the result as i want .

    var vGreenTXJSON = {};
    angular.extend(vGreenTXJSON ,vGreenTxData.GTX_INNER_JOIN );
    angular.extend(vGreenTXJSON ,vGreenTxData.GTX_LEFT_OUTER_JOIN );
    angular.extend(vGreenTXJSON ,vGreenTxData.GTX_RIGHT_OUTER_JOIN );

I want single JSON eg

[{},{},{},{},{},{},{},{},{},{},{},{},{},{},{},{},{},{},{},{}‌​,{},{},{},...]

like this , but this is creating array of JSON like :

object :

[GTX_INNER_JOIN :[{},{},{},{},{},....],

GTX_LEFT_OUTER_JOIN:[{},{},{},{},{},.‌​...],

GTX_RIGHT_OUTER‌​_JOIN:[{},{},{},{},{‌​},....]]

Answer 1

it can be very helpful to specify the result you're expecting. you can do -

var vGreenTXJSON = {
    innerJoin: vGreenTxData.GTX_INNER_JOIN,
    leftOuterJoin: vGreenTxData.GTX_LEFT_OUTER_JOIN,
    rightOuterJoin: vGreenTxData.GTX_RIGHT_OUTER_JOIN
};

Answer 2

If you directly copy all properties of vGreenTxData to vGreenTXJSON , you could use below.

angular.extend(vGreenTXJSON ,vGreenTxData);

If you want to specifically grab some of Props from vGreenTxData object then it would be look like below.

angular.extend(vGreenTXJSON ,{
    GTX_InnerJoin: vGreenTxData.GTX_INNER_JOIN,
    GTX_OuterJoin: vGreenTxData.GTX_LEFT_OUTER_JOIN,
    GTX_Right_OuterJoin: vGreenTxData.GTX_RIGHT_OUTER_JOIN
});