How to make if statement keep working after clicking on a button once

Question

I will try to explain it better. I rewrote a code, to make it better as an example. As you can see I have an app to generate a number, but to generate correct number I have to click 5-15 times on a button, due to random and if statement. I want to ask how to make a process to skip incorrect numbers and give an actual answers ( which took 5-15 clicks ) only in one click. I can give more information, if you didn't understand me. Thank you very much!

*video: https://vimeo.com/251109159

  function getnumber() {
  var input = document.IX.onetoThou.value;

  var firstNum = input[0];

  var ranNumb = Math.floor(Math.random()*(99-00+1)+00);
  var ans = "you are right!";

  var newNumber = firstNum + ranNumb;

  if ( newNumber % 5 == 0){
    document.getElementById("newnumber").innerHTML = newNumber+" "+ans;
    }
  }

Answer 1

You can wrap the generation of your number inside a do while loop:

function getnumber() {
  var input = document.IX.onetoThou.value;
  var firstNum = input[0];
  var ans = "you are right!";
  var newNumber;
  do {
    var ranNumb = Math.floor(Math.random()*(99-00+1)+00);
    newNumber = firstNum + ranNumb;
  } while (newNumber % 5 !== 0); 

  document.getElementById("newnumber").innerHTML = newNumber+" "+ans;

}

Answer 2

不是在[0,100）中生成随机整数并检查它是否为5的倍数，而是在[0,20]中生成随机整数并将其乘以5.这样可以保证结果为5的倍数。在0到100之间。

var ranNumb = Math.floor(Math.random() * 20) * 5;

Answer 3

hope this might help. You have to use if-else rather then if conditional statement

function getnumber() {
  var input = document.IX.onetoThou.value;

  var firstNum = input[0];

  var ranNumb = Math.floor(Math.random()*(99-00+1)+00);
  var ans = "you are right!";

  var newNumber = firstNum + ranNumb;

  if ( newNumber % 5 == 0){
    document.getElementById("newnumber").innerHTML = newNumber+" "+ans;
    }else{
document.getElementById("newnumber").innerHTML = "You are wrong";
    }

  }