I need to launch a process within a shell script. (It is a special logging process.) It needs to live for most of the shell script, while some other processes will run, and then at the end we will kill it.
A problem that I am having is that I need to launch this process, and wait for it to "warm up", before proceeding to launch more processes.
I know that I can wait for a line of input from a pipe using read
, and I know that I can spawn a child process using &
. But when I use them together, it doesn't work like I expect.
As a mockup:
When I run this (sequential):
(sleep 1 && echo "foo") > read
my whole shell blocks for 1 second, and the echo of foo
is consumed by read, as I expect.
I want to do something very similar, except that I run the "foo"
job in parallel:
(sleep 1 && echo "foo" &) > read
But when I run this, my shell doesn't block at all, it returns instantly -- I don't know why the read doesn't wait for a line to be printed on the pipe?
Is there some easy way to combine "spawning of a job" ( &
) with capturing the stdout pipe within the original shell ?
An example that is very close to what I actually need is, I need to rephrase this somehow,
(sleep 1 && echo "foo" && sleep 20 &) > read; echo "bar"
and I need for it to print "bar"
after exactly one second, and not immediately, or 21 seconds later.
Here's an example using named pipes, pretty close to what I used in the end. Thanks to Luis for his comments suggesting named pipes.
#!/bin/sh
# Set up temporary fifo
FIFO=/tmp/test_fifo
rm -f "$FIFO"
mkfifo "$FIFO"
# Spawn a second job that writes to FIFO after some time
sleep 1 && echo "foo" && sleep 20 >$FIFO &
# Block the main job on getting a line from the FIFO
read line <$FIFO
# So that we can see when the main job exits
echo $line
Thanks also to commenter Emily E., the example that I posted that was misbehaving was indeed writing to a file called read
instead of using the shell-builtin command read
.
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