Adding if statement in a try/except bloc

Question

I' learning Python and I wonder if improving my code with a light debug level with if statement in my try/except bloc may be a good practice or if there is a better (or builtin) way to doing this.

#!/usr/bin/env python3
""" Testing conditions in try/except """

DEBUG_MODE = True
number = input("Type a integer: ")

try:
    number = int(number)
except ValueError as except_detail:
    if DEBUG_MODE:
        print("ValueError: «{}»".format(except_detail))
    else:
        print("«{}» is not an integer".format(number))            
else:
    print("Your number {} is an integer".format(number))

I use a boolean, but a debug-level list() work either for more than 2 levels.

Error reporting may also be improved with debug-level specific logging instructions.

Answer 1

You could use Python's logging module for this, you can change the logging level argument to record the level of logging detail you want:

import logging

logging.basicConfig(filename='log.txt', filemode='a', level=logging.DEBUG)

try:
    number = int(number)
except ValueError as except_detail:
    logging.warning("ValueError: «{}»".format(except_detail))
    logging.info("«{}» is not an integer".format(number))         
else:
    logging.info("Your number {} is an integer".format(number))

Answer 2

标准库具有为此目的而设计的日志记录模块： https : //docs.python.org/2/library/logging.html内置了日志级别的调试，信息，警告，错误，严重