How can I use Throws with multiple if/else conditions?

Question

I have a method using throws, inside is two if/else statements, the if statement tests a condition and then throws an exception if it fails, the problem is of course is that if the first if/else block fails my second never gets executed, is there an alternative way to approach this problem?

EDIT (Further Information)

My code is checking whether a person object has the correct first name Test 1, or the correct surname Test 2, if not throw exception A or B, code further on then adds the person into a group if they pass both conditions

  Method throws Exception A, Exception B
{
    //Test First name 
    if(Test1)
    {
      If persons firstname is correct, Test1 is true
    }
    else
    {
      throw new Exception A
    }

    //Test Surname
    if(Test2)
    {
      If persons surname is correct, Test2 is true
    }
    else
    {
      throw new Exception B
    }

   //If everything is fine, add the person to a list.
   if (Test1 & Test2)
   {
     Add Person to a list
   }
}

Answer 1

Based upon your description, I am thinking that you could change to

if(Test1)
{
    if(!Test2)
    {
       throw new Exception B
    }
    // Do some work here
}
else
{
  throw new Exception A
}

Another way to consider is by creating methods

bool test1 = correctFirstName (fname);
bool test2 = correctLastName (lname);

if (test1 && test2) 
{
    // do some stuff
}
else {
    if (!test1) // throw ExceptionA
    else // throw ExceptionB
}

Answer 2

Something like this should work. I would of course recommend not using generic Exception, but I would also not use two different types of exceptions as your original code implied.

  Method throws Exception A, Exception B
{
    String errMsg = "";

    //Test First name 
    if(Test1)
    {
      If persons firstname is correct, Test1 is true
    }
    else
    {
      errMsg = "Invalid first name";
    }

    //Test Surname
    if(Test2)
    {
      If persons surname is correct, Test2 is true
    }
    else
    {
      errMsg = "Invalid surname";
    }

   //If everything is fine, add the person to a list.
   if (errMsg.equals(""));
   {
     Add Person to a list
   }
   else
   {
      throw new Exception(errMsg);
   }
}

Answer 3

看来该任务是不可能的，发给我的指令没有说明要触发一个Exception或另一个我必须注释掉代码。