I've got two dictionaries of unequal length, eg:
people = {"john" : "carpenter", "jill": "locksmith", "bob":"carpenter", "jane": "pilot", "dan": "locksmith"}
jobcode = {"carpenter": 1, "locksmith": 2, "pilot": 3}
What I'm wanting to do is replace the values in people
with the jobcode
value. So youd end up with: n
people = {"john": 1, "jill": 2, "bob": 1, "jane": 3, "dan":2}
I'd be happy to make another new dict
that encapsulates this new data as well but so far the closest I think I've come is this ... I think...
Any help would be greatly appreciated.
You can easily achieve this with dict comprehension
{k: jobcode[v] for k, v in people.items()}
However you should be careful since it can raise KeyError
.
Another way with default jobcode
with dict
.get()
method :
default_jobcode = 1000
final_dict = {k: jobcode.get(v, default_jobcode) for k, v in people.items()}
UPDATE
As @Graipher kindly noted, if jobcode
dict is lack of key-value pair, you can leave item untouched as such:
final_dict = {k: jobcode.get(v, v) for k, v in people.items()}
Which is probably better solution that having default jobcode
.
Ty this:-
people = {'john' : 'carpenter', 'jill': 'locksmith', 'bob':'carpenter', 'jane': 'pilot', 'dan': 'locksmith'}
jobcode = {'carpenter': 1, 'locksmith': 2, 'pilot': 3}
for i,j in people.items():
if j in jobcode.keys():
people[i] = jobcode[j]
print(people)
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