When I run the code below my program crashes, and I believe this is to-do with the .text() called when the Line edit has something typed in it. I need to assign a variable to what is entered here.
import sys
from PyQt5.QtWidgets import *
from PyQt5 import QtWidgets
class loginScreen(QtWidgets.QWidget):
def __init__(self):
super().__init__()
self.initUI()
def initUI(self):
usernameBox = QtWidgets.QLineEdit()
usernameBox.textChanged.connect(self.myfunc)
vArrangement = QtWidgets.QVBoxLayout()
vArrangement.addWidget(usernameBox)
self.setLayout(vArrangement)
self.show()
def myfunc(self):
x = usernameBox.text()
print(x)
if __name__ == '__main__':
app = QApplication(sys.argv)
ex = loginScreen()
sys.exit(app.exec_())
If you observe usernameBox
it is created as a local variable so it can not be accessed by the other methods of the class, in your case there are 2 solutions:
class loginScreen(QtWidgets.QWidget):
def __init__(self):
super().__init__()
self.initUI()
def initUI(self):
self.usernameBox = QtWidgets.QLineEdit()
self.usernameBox.textChanged.connect(self.myfunc)
vArrangement = QtWidgets.QVBoxLayout()
vArrangement.addWidget(self.usernameBox)
self.setLayout(vArrangement)
self.show()
def myfunc(self):
x = self.usernameBox.text()
print(x)
sender()
that obtains the object that emits the signal, in your case the QLineEdit
. class loginScreen(QtWidgets.QWidget):
def __init__(self):
super().__init__()
self.initUI()
def initUI(self):
usernameBox = QtWidgets.QLineEdit()
usernameBox.textChanged.connect(self.myfunc)
vArrangement = QtWidgets.QVBoxLayout()
vArrangement.addWidget(usernameBox)
self.setLayout(vArrangement)
self.show()
def myfunc(self):
x = self.sender().text()
print(x)
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