Access SQL to create new record for each record in another table

Question

DB Structure

Table: tbl_dateLog
    Field: ID (Autonumber)
    Field: dateEntry(Date Format)

Table: tbl_technician
    Field: ID (Auto number format)
    Field: fname (string format)
    Field: lname (string format)

Table: tbl_entries
    Field: ID (Auto number format)
    Field: dateID (number format)
    Field: techID (number format)
    Field: totalClaims (number format)

I have been searching for a solution for quite a while. I believe the answer is simple, but it keeps eluding me.

I would like to add a new record for Today's date using Date() in tbl_dateLog. Then loop an INSERT INTO query that will add a new record in tbl_entries for each tbl_technicians.ID , place a zero for the tbl_entries.totalClaims field, and place the tbl_dateLog.ID in the tbl_entries.dateID field.

I hoped something like this would get me on the right track, but I'm sure I will need a type of JOINS to add the dateID:

INSERT INTO tbl_entries (techID,totalClaims) select ID, 0 FROM tbl_technician

I am having a lot of trouble tying this all together and searching for an answer has confused me even more. I am using Access 2016.

Answer 1

I would like to add a new record for Today's date using Date() in tbl_dateLog.

INSERT INTO tbl_dateLog
( 
dateEntry
) 
SELECT 
Date()
;

Then loop an INSERT INTO query that will add a new record in tbl_entries for each tbl_technicians.ID, place a zero for the tbl_entries.totalClaims field, and place the tbl_dateLog.ID in the tbl_entries.dateID field.

 INSERT INTO tbl_entries
(
dateID,
techID,
totalClaims
)
SELECT
(SELECT [tbl_dateLog]![ID] FROM [tbl_dateLog] where [tbl_dateLog]![dateEntry] = DATE()),
tbl_technician.ID,
0
FROM
    tbl_technician
;