Multiple conditions on bash 'if' statement

Question

i'm having trouble with if in bash. basically i'm trying to do this in bash:

if ((x='r')&&(y='s'))||((x='s')&&(y='p')) then
echo "bluh"

but i've just can't find the proper way, used square brackets, 2 square brackets, round brackets.

but it just won't work...

Answer 1

(( )) are for bash arithmetic , instead you need [[ ]] bash test :

if [[ ( $x == r && $y == s ) || ( $x == s && $y == p ) ]]; then
    echo "bluh"
fi

[[ is a bash keyword similar to (but more powerful than) the [ command. See http://mywiki.wooledge.org/BashFAQ/031 and http://mywiki.wooledge.org/BashGuide/TestsAndConditionals . Unless you're writing for POSIX sh, we recommend [[ .