Object of type 'TypeError' is not JSON serializable

Question

I try to build API with Django rest framework

And I got Object of

type 'TypeError' is not JSON serializable

What should I do to fix?

Here's my view.py

class NewsViewSet(viewsets.ModelViewSet):
    queryset = News.objects.all()
    serializer_class = NewsSerializer

    def list(self, request, **kwargs):
        try:
            nba = query_nba_by_args(**request.query_params)
            serializer = NewsSerializer(nba['items'], many=True)
            result = dict()
            result['data'] = serializer.data
            result['draw'] = nba['draw']
            result['recordsTotal'] = nba['total']
            result['recordsFiltered'] = nba['count']
            return Response(result, status=status.HTTP_200_OK, template_name=None, content_type=None)

        except Exception as e:
            return Response(e, status=status.HTTP_404_NOT_FOUND, template_name=None, content_type=None)

Answer 1

Django cannot convert Exception object to JSON format and raise error. To fix it you should convert error to string and pass result to response:

except Exception as e:
    return Response(str(e), status=status.HTTP_404_NOT_FOUND, template_name=None, content_type=None)

Answer 2

first

import json
from django.http import HttpResponse

Change line

  return Response(result, status=status.HTTP_200_OK, template_name=None, content_type=None)

for this

   return HttpResponse(json.dumps(result),content_type="application/json")

or use

 from django.http import JsonResponse

 return JsonResponse(json.dumps(result))

Answer 3

Python exceptions are not json serializable. It's failing in try because of some connection or content unavailable issue, then going into except block where you are passing exception e as it is to Response() so that is creating the issue. Solution - check the URL and also in except block convert exception e to string and pass to Response(str(e), status=status.HTTP_404_NOT_FOUND, template_name=None, content_type=None) .